Mathematical Analysis

1. Power output,
Brake power,bp = 2pNT/60 watt
Where,
N = Speed in rpm
T = Torque in N-m
T = Fb
F = Mechanical load on engine shaft in Newton
b = Radious of the brake dynamometer in meter
2. Mass of fuel consumption, mf = ??*3600/t*1000 kg/hr
3. Brake specific fuel consumption, (bsfc) = mf/bp kg/kw-hr

Where,

mf =Mass of fuel consumed in kg/hr
bp = brake power in kw

4.Brake thermal efficiency =bp*3600*100/(mf*CV ) %

Calculation:

1. Brake power, bp= 2*?*800*14.80*0.35/ (60*1000)
= .433 kW

2. Mass flow rate, mf

Volume per second, V=10*10-6/63 m3/sec
= 0.153*10-6 m3/sec

Mass flow rate, mf = ?*V
= 850*0.158*10-6 kg/sec
= 134.3*10-6 * 3600 kg/hr
= 0.483 kg/hr

3. Specific fuel consumption, sfc = mf / BP
= 0.483 / 0.433
= 1.115 kg/ kw-hr

4. Efficiency, ? = (BP * 3600) / (mf * C)
= (0.433 * 3600) / (0.483 * 43000)
= 7.5 %